To solve the problem, we first need to determine the degree measures for both the 11:00 position and the 4:00 position on the clock.
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The positions on a clock represent the following degree measures:
- Each hour marks 30 degrees because \( \frac{360 \text{ degrees}}{12 \text{ hours}} = 30 \text{ degrees/hour} \).
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The 11:00 position:
- To find the degree measure for 11:00: \[ 11 \times 30 = 330 \text{ degrees} \]
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The 4:00 position:
- To find the degree measure for 4:00: \[ 4 \times 30 = 120 \text{ degrees} \]
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Next, we calculate the clockwise angle formed when moving from the 11:00 position (330 degrees) to the 4:00 position (120 degrees).
- Since we are moving clockwise, we can simply subtract the two angle measures: \[ 120 \text{ degrees} - 330 \text{ degrees} = -210 \text{ degrees} \]
- Since this is a negative angle (indicating a clockwise rotation), we can find the equivalent positive angle by adding 360 degrees: \[ -210 + 360 = 150 \text{ degrees} \]
Thus, the degree measure of the angle formed moving clockwise from the 11:00 position to the 4:00 position is:
\[ \boxed{150} \text{ degrees} \]