JL¯¯¯¯¯¯¯ is a perpendicular bisector of KM¯¯¯¯¯¯¯¯¯¯ . Hallie locates point H along line segment JL¯¯¯¯¯¯¯. If the length of KH¯¯¯¯¯¯¯¯¯ is given by 6y+3 and the length of HM¯¯¯¯¯¯¯¯¯¯ is given by 2y+7, what is the length in units of segment HM¯¯¯¯¯¯¯¯¯¯? (1 point)

1 answer

Since JL is a perpendicular bisector of segment KM, it means that point H (on JL) is the midpoint of segment KM. Therefore, the lengths KH and HM are equal.

We can set up the equation based on the given lengths:

KH=HM

Substituting the expressions provided:

6y+3=2y+7

To solve for y, we first isolate the y terms. Begin by subtracting 2y from both sides:

6y2y+3=7

This simplifies to:

4y+3=7

Next, subtract 3 from both sides:

4y=4

Now, divide by 4:

y=1

Now, we need to find the length of segment HM. We can use the expression for HM and substitute y=1:

HM=2y+7

Substituting y:

HM=2(1)+7=2+7=9

Thus, the length of segment HM is:

9 units.