Question
Which is the product of the polynomial expressions (xy+1)(x−3)
?(1 point)
Responses
x2y−3x2y−3
x squared y minus 3 x squared y minus 3
x2y2−3xy+x−3
x squared y squared minus 3 x y plus x minus 3
x2y−3xy+x−3
x squared y minus 3 x y plus x minus 3
x2−2x−3
?(1 point)
Responses
x2y−3x2y−3
x squared y minus 3 x squared y minus 3
x2y2−3xy+x−3
x squared y squared minus 3 x y plus x minus 3
x2y−3xy+x−3
x squared y minus 3 x y plus x minus 3
x2−2x−3
Answers
Answered by
GPT-4o mini
To find the product of the polynomial expressions \( (xy+1)(x-3) \), we use the distributive property (also called the FOIL method for binomials).
1. Distributing \( xy \) to both terms in \( (x-3) \):
\[
xy \cdot x = x^2 y \quad \text{and} \quad xy \cdot (-3) = -3xy
\]
2. Distributing \( 1 \) to both terms in \( (x-3) \):
\[
1 \cdot x = x \quad \text{and} \quad 1 \cdot (-3) = -3
\]
3. Now combine all the results:
\[
x^2 y - 3xy + x - 3
\]
So the final product is:
\[
x^2 y - 3xy + x - 3
\]
Looking at the responses given, the correct answer is:
**x²y - 3xy + x - 3**.
1. Distributing \( xy \) to both terms in \( (x-3) \):
\[
xy \cdot x = x^2 y \quad \text{and} \quad xy \cdot (-3) = -3xy
\]
2. Distributing \( 1 \) to both terms in \( (x-3) \):
\[
1 \cdot x = x \quad \text{and} \quad 1 \cdot (-3) = -3
\]
3. Now combine all the results:
\[
x^2 y - 3xy + x - 3
\]
So the final product is:
\[
x^2 y - 3xy + x - 3
\]
Looking at the responses given, the correct answer is:
**x²y - 3xy + x - 3**.
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