To solve the system of equations, we have:
- \( 2x + y = 15 \) (Equation 1)
- \( y = -x + 5 \) (Equation 2)
We can substitute the expression for \( y \) from Equation 2 into Equation 1.
Substituting \( y = -x + 5 \) into Equation 1:
\[ 2x + (-x + 5) = 15 \]
Now, simplify this equation:
\[ 2x - x + 5 = 15 \]
This simplifies to:
\[ x + 5 = 15 \]
Now, subtract 5 from both sides:
\[ x = 10 \]
Now that we have the value of \( x \), we can substitute it back into Equation 2 to find \( y \):
\[ y = -x + 5 \]
Substituting \( x = 10 \):
\[ y = -10 + 5 = -5 \]
Thus, the coordinates of the intersection point that solves the system of equations are:
\[ \boxed{(10, -5)} \]