3/2 (4-8x) + 5x = 1 - 7x

To solve the equation \( \frac{3}{2} (4 - 8x) + 5x = 1 - 7x \), we can follow these steps:

1. Distribute \( \frac{3}{2} \) to the terms inside the parentheses:
\[
\frac{3}{2} \cdot 4 - \frac{3}{2} \cdot 8x = 6 - 12x
\]
So, the equation becomes:
\[
6 - 12x + 5x = 1 - 7x
\]

2. Combine like terms on the left side:
\[
6 - 7x = 1 - 7x
\]

3. Since both sides have \(-7x\), we can add \(7x\) to both sides to eliminate \(-7x\):
\[
6 = 1
\]

4. This is a contradiction (since \(6\) does not equal \(1\)), which indicates that there is no solution to the equation.

Therefore, the conclusion is that the equation has **no solution**.