To determine which system has the point (0, -2) as a solution, we will substitute \(x = 0\) and \(y = -2\) into each equation of the provided options. If both equations of a system are satisfied, then (0, -2) is a solution for that system.
Option A:
-
\(x + y = 2\)
Substitute: \(0 + (-2) = 2\)
Result: \(-2 \neq 2\) (not satisfied) -
\(-x + 2y = 16\)
Substitute: \(-0 + 2(-2) = 16\)
Result: \(-4 \neq 16\) (not satisfied)
Conclusion for A: Not a solution.
Option B:
-
\(-5x + y = -2\)
Substitute: \(-5(0) + (-2) = -2\)
Result: \(-2 = -2\) (satisfied) -
\(-3x + 6y = -12\)
Substitute: \(-3(0) + 6(-2) = -12\)
Result: \(-12 = -12\) (satisfied)
Conclusion for B: Is a solution.
Option C:
-
\(-4x + y = 6\)
Substitute: \(-4(0) + (-2) = 6\)
Result: \(-2 \neq 6\) (not satisfied) -
\(-5x - y = 21\)
Substitute: \(-5(0) - (-2) = 21\)
Result: \(2 \neq 21\) (not satisfied)
Conclusion for C: Not a solution.
Option D:
-
\(-5x = y - 3\)
Substitute: \(-5(0) = -2 - 3\)
Result: \(0 \neq -5\) (not satisfied) -
\(3x - 8y = 24\)
Substitute: \(3(0) - 8(-2) = 24\)
Result: \(16 \neq 24\) (not satisfied)
Conclusion for D: Not a solution.
After evaluating all options, we find that the point (0, -2) is a solution to Option B: \(-5x + y = -2\) and \(-3x + 6y = -12\).