Asked by JIM
You commute 56 miles one way to work. The trip to work takes 10 minutes longer than the trip home. Your average speed on the trip home is 8 miles per hour faster. What is your average speed on the trip home?
I got to this point
xy=56
(x-8)(y+10)=56
I couldn't get any further than that. I'm not sure where to go with those equations.
I got to this point
xy=56
(x-8)(y+10)=56
I couldn't get any further than that. I'm not sure where to go with those equations.
Answers
Answered by
bobpursley
Ok, then x=56/y
(56/y -8)*(y+10/60)=56
multiply both sides by y.
y(56/y -8)*(y+10/60)=56y
(56 -8y)*(y+10/60)=56y
FOIL that, and solve the quadratic for y. ONce you get that, you can solve for x.
Note:
The fraction 10/60 is important..the ten was in minutes, and it has to be converted to hours, as speed was given in km/hr (remember the units given for 8).
(56/y -8)*(y+10/60)=56
multiply both sides by y.
y(56/y -8)*(y+10/60)=56y
(56 -8y)*(y+10/60)=56y
FOIL that, and solve the quadratic for y. ONce you get that, you can solve for x.
Note:
The fraction 10/60 is important..the ten was in minutes, and it has to be converted to hours, as speed was given in km/hr (remember the units given for 8).
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