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Question

Place the numbers in descending order.

2.3 × 10−10 ; 3.2 × 10−10 ; 2.3 × 10−12 ; 2.3 × 10−8

(2 points)

1 answer

To arrange the numbers \(2.3 \times 10^{-10}\), \(3.2 \times 10^{-10}\), \(2.3 \times 10^{-12}\), and \(2.3 \times 10^{-8}\) in descending order, we can compare their values.

  1. \(2.3 \times 10^{-8} = 0.000000023\)
  2. \(2.3 \times 10^{-10} = 0.00000000023\)
  3. \(3.2 \times 10^{-10} = 0.00000000032\)
  4. \(2.3 \times 10^{-12} = 0.0000000000023\)

Now, we'll order them:

  1. \(2.3 \times 10^{-8}\)
  2. \(3.2 \times 10^{-10}\)
  3. \(2.3 \times 10^{-10}\)
  4. \(2.3 \times 10^{-12}\)

Putting these in descending order, we have:

Descending Order:

  1. \(2.3 \times 10^{-8}\)
  2. \(3.2 \times 10^{-10}\)
  3. \(2.3 \times 10^{-10}\)
  4. \(2.3 \times 10^{-12}\)