What is the length of the hypotenuse of a 30-60-90 triangle if the side opposite the 60-degree angle is 6sqrt3

1 answer

In a 30-60-90 triangle, the lengths of the sides are in a specific ratio:

  • The side opposite the 30-degree angle is \( x \).
  • The side opposite the 60-degree angle is \( x\sqrt{3} \).
  • The hypotenuse is \( 2x \).

Given that the side opposite the 60-degree angle is \( 6\sqrt{3} \), we have:

\[ x\sqrt{3} = 6\sqrt{3} \]

To find \( x \), we can divide both sides by \( \sqrt{3} \):

\[ x = 6 \]

Now that we have \( x \), we can determine the length of the hypotenuse:

\[ \text{Hypotenuse} = 2x = 2 \times 6 = 12 \]

Therefore, the length of the hypotenuse is \( \boxed{12} \).