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Suppose you discovered a new multicellular organism that is shaped like a cube. The organism measures 3 cells tall, 3 cells wid...Question
Suppose you discovered a new multicellular organism that is shaped like a cube. The organism measures 3 cells tall, 3 cells wide, and 3 cells deep. You measure one cubed cell to be 2 arbitrary units per side. Can you calculate this organism’s surface area to volume ratio?
Find the surface area, volume, and surface area to volume ratio
Find the surface area, volume, and surface area to volume ratio
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Answered by
GPT-4o mini
To find the surface area, volume, and surface area to volume ratio of the new cubical organism, we can follow these steps:
### Step 1: Determine the dimensions of the organism
The organism has dimensions of 3 cells tall, 3 cells wide, and 3 cells deep. Given that each cubed cell measures 2 arbitrary units per side, we can calculate the overall dimensions of the organism in arbitrary units.
- Height = 3 cells × 2 units/cell = 6 units
- Width = 3 cells × 2 units/cell = 6 units
- Depth = 3 cells × 2 units/cell = 6 units
### Step 2: Calculate the volume
The volume \( V \) of a cuboid is given by the formula:
\[
V = \text{Height} \times \text{Width} \times \text{Depth}
\]
Substituting the dimensions we found:
\[
V = 6 \, \text{units} \times 6 \, \text{units} \times 6 \, \text{units} = 216 \, \text{cubic units}
\]
### Step 3: Calculate the surface area
The surface area \( A \) of a cuboid is given by the formula:
\[
A = 2(\text{Height} \times \text{Width} + \text{Height} \times \text{Depth} + \text{Width} \times \text{Depth})
\]
Substituting the dimensions:
\[
A = 2(6 \, \text{units} \times 6 \, \text{units} + 6 \, \text{units} \times 6 \, \text{units} + 6 \, \text{units} \times 6 \, \text{units})
\]
\[
A = 2(36 + 36 + 36) = 2(108) = 216 \, \text{square units}
\]
### Step 4: Calculate the surface area to volume ratio
The surface area to volume ratio \( R \) is given by:
\[
R = \frac{A}{V}
\]
Substituting the values we calculated:
\[
R = \frac{216 \, \text{square units}}{216 \, \text{cubic units}} = 1 \, \text{(arbitrary units)}^{-1}
\]
### Summary of Results
- **Surface Area**: 216 square units
- **Volume**: 216 cubic units
- **Surface Area to Volume Ratio**: 1 (arbitrary units)^{-1}
### Step 1: Determine the dimensions of the organism
The organism has dimensions of 3 cells tall, 3 cells wide, and 3 cells deep. Given that each cubed cell measures 2 arbitrary units per side, we can calculate the overall dimensions of the organism in arbitrary units.
- Height = 3 cells × 2 units/cell = 6 units
- Width = 3 cells × 2 units/cell = 6 units
- Depth = 3 cells × 2 units/cell = 6 units
### Step 2: Calculate the volume
The volume \( V \) of a cuboid is given by the formula:
\[
V = \text{Height} \times \text{Width} \times \text{Depth}
\]
Substituting the dimensions we found:
\[
V = 6 \, \text{units} \times 6 \, \text{units} \times 6 \, \text{units} = 216 \, \text{cubic units}
\]
### Step 3: Calculate the surface area
The surface area \( A \) of a cuboid is given by the formula:
\[
A = 2(\text{Height} \times \text{Width} + \text{Height} \times \text{Depth} + \text{Width} \times \text{Depth})
\]
Substituting the dimensions:
\[
A = 2(6 \, \text{units} \times 6 \, \text{units} + 6 \, \text{units} \times 6 \, \text{units} + 6 \, \text{units} \times 6 \, \text{units})
\]
\[
A = 2(36 + 36 + 36) = 2(108) = 216 \, \text{square units}
\]
### Step 4: Calculate the surface area to volume ratio
The surface area to volume ratio \( R \) is given by:
\[
R = \frac{A}{V}
\]
Substituting the values we calculated:
\[
R = \frac{216 \, \text{square units}}{216 \, \text{cubic units}} = 1 \, \text{(arbitrary units)}^{-1}
\]
### Summary of Results
- **Surface Area**: 216 square units
- **Volume**: 216 cubic units
- **Surface Area to Volume Ratio**: 1 (arbitrary units)^{-1}
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