To solve the quadratic equation \( x^2 - 10x + 24 = 0 \), we can factor the expression.
We are looking for two numbers that multiply to \( 24 \) (the constant term) and add to \( -10 \) (the coefficient of the linear term).
The numbers \( -4 \) and \( -6 \) meet these criteria:
\[ (-4) \times (-6) = 24 \] \[ (-4) + (-6) = -10 \]
So we can factor the quadratic as:
\[ (x - 4)(x - 6) = 0 \]
Setting each factor equal to zero gives us:
\[ x - 4 = 0 \quad \Rightarrow \quad x = 4 \] \[ x - 6 = 0 \quad \Rightarrow \quad x = 6 \]
Thus, the solutions to the equation \( x^2 - 10x + 24 = 0 \) are \( x = 4 \) and \( x = 6 \).
Among the provided options, the correct answer is:
Both x=4 and x=6 are solutions.