Asked by Jacob
A 1.50 M solution containing 25 Grams of Al(OH)3 would occupy what volume in liters?
Answers
Answered by
DrBob222
1.5 moles/L of solution.
How many moles do we have in 25 g.
25/molar mass Al(OH)3.
M = moles/L
You know M (1.5) and you know moles. Solve for L.
How many moles do we have in 25 g.
25/molar mass Al(OH)3.
M = moles/L
You know M (1.5) and you know moles. Solve for L.
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