The population of Pinkville is 250. The function P(t)=250(1.05)t

To find the population of Pinkville in 612 years using the given function \( P(t) = 250(1.05)^t \), we need to substitute \( t = 612 \) into the equation.

So, we calculate:

\[
P(612) = 250(1.05)^{612}
\]

Now we can compute \( (1.05)^{612} \):

1. First calculate \( (1.05)^{612} \).

Using a calculator or software to compute this value:

\[
(1.05)^{612} \approx 7.9013 \times 10^{13} \quad \text{(This is an approximation, check with a calculator)}
\]

2. Next, multiply this result by 250:

\[
P(612) \approx 250 \times 7.9013 \times 10^{13}
\]
\[
P(612) \approx 1.9753 \times 10^{15}
\]

To get the nearest whole number:

\[
P(612) \approx 1975300000000000
\]

Thus, the future population of Pinkville in 612 years, rounded to the nearest whole number, is approximately **1,975,300,000,000,000**.