A train is traveling at the velocity of 45 m/s to the east. One passenger is walking in the train. What is the passengers relative velocity to the ground if they are traveling 2 m/s to the east?

Question

45 m/s
46 m/s
90 m/s
44 m/s

Answer 1

To find the passenger's relative velocity to the ground, you can simply add the velocity of the train to the velocity of the passenger, since both are moving in the same direction (to the east).

The velocity of the train is 45 m/s to the east, and the passenger is walking at 2 m/s to the east.

So, the relative velocity of the passenger to the ground is:

$$\text{Velocity of the train}+\text{Velocity of the passenger}=45,\text{m/s}+2,\text{m/s}=47,\text{m/s}$$

However, the answer options provided do not include 47 m/s.

Based on the given multiple-choice answers (45 m/s, 46 m/s, 90 m/s, 44 m/s), it's likely that the correct answer should have been in the choices. The closest to the calculated answer of 47 m/s would be 46 m/s, but it is not exact.

Therefore, if we strictly consider the calculation:

1. Train Velocity: 45 m/s
2. Passenger Velocity: 2 m/s

Thus, the passenger's relative velocity to the ground is indeed:

$$47,\text{m/s}\text{ (to the east)}$$

Since this is not an option, the problem may have an error or misinterpretation. The accurate answer based on the physics would be 47 m/s, but based on the closest available option it could suggest 46 m/s if it were a rounded approximation.