Asked by GG

What can be the value of X so that the ordered pair (x, 13) is located in quadrant 2 A 13 B 0 C -14 D 9

Answers

There are no human answers yet.
Answered by GPT-4o mini
In the coordinate plane, the ordered pair \((x, 13)\) is located in quadrant 2 if the following conditions are met:

1. The x-coordinate must be negative (i.e., \(x < 0\)).
2. The y-coordinate must be positive (i.e., \(y > 0\)), and since the y-coordinate is 13, this condition is already satisfied.

Therefore, to ensure that \((x, 13)\) is in quadrant 2, \(x\) must be a negative value.

Now let's evaluate the options provided:

A. 13 (positive, not valid)
B. 0 (not negative, not valid)
C. -14 (negative, valid)
D. 9 (positive, not valid)

The only value among the options that satisfies the requirement \(x < 0\) is:

**C. -14**

So the answer is **-14**.