Asked by Felicity
Alright, so I'm doing questions on exponent laws for my grade 11 math couse, and I came across one and I've no idea how to answer it. Could someone please explain step by step? According to textbook, answer should be 16:
(2^3) / [(2^0)-(2^-1)]
That "-1" is a negative exponent in the last bit, just so you know.
(2^3) / [(2^0)-(2^-1)]
That "-1" is a negative exponent in the last bit, just so you know.
Answers
Answered by
MathMate
Some of the exponential laws state that:
a<sup>0</sup>=1
a<sup>1</sup>=a
a<sup>-b</sup>=1/a<sup>b</sup>
In your case, a=2 (the base).
So these laws should enable you to evaluate each term of the denominator.
The answer should indeed be 16.
I appreciate your having inserted sufficient parentheses to render the expression unambiguous.
a<sup>0</sup>=1
a<sup>1</sup>=a
a<sup>-b</sup>=1/a<sup>b</sup>
In your case, a=2 (the base).
So these laws should enable you to evaluate each term of the denominator.
The answer should indeed be 16.
I appreciate your having inserted sufficient parentheses to render the expression unambiguous.
Answered by
Felicity
I hope I'm not asking too much, but it would be ace if you would type out the problem and the path to solving it just so I can compare and see where I'm going wrong?
Answered by
MathMate
Here it is. Post if help is needed.
(2^3) / [(2^0)-(2^-1)]
=8/(2^0-2^-1)
=8/(1- 1/2¹)
=8/(1- 1/2)
=8/(1/2)
=16
(2^3) / [(2^0)-(2^-1)]
=8/(2^0-2^-1)
=8/(1- 1/2¹)
=8/(1- 1/2)
=8/(1/2)
=16
There are no AI answers yet. The ability to request AI answers is coming soon!