Use the image to answer the question.

To locate the Fuji apples, we look for the coordinates of Fuji, which is plotted in Quadrant 2. According to your description, Fuji is shown at 3 increments on the x-axis (which is negative in Quadrant 2) and 2 increments on the y-axis (which is positive in Quadrant 2).

Thus, the coordinates for Fuji are:

**(−3, 2)**

So the correct response for locating the Fuji apples is:

**4. (−3, 2)**

Solve the following problem:

What is the distance from (−13, 12) to (−13, −77) ?

(1 point)
Responses

65
65

26
26

89
89

−89

To find the distance between the points \((-13, 12)\) and \((-13, -77)\), we can use the distance formula. However, since both points have the same x-coordinate, the distance between them is simply the difference in their y-coordinates.

The distance \(d\) can be calculated as:

\[
d = |y_2 - y_1| = |-77 - 12| = |-89| = 89
\]

Thus, the distance from \((-13, 12)\) to \((-13, -77)\) is:

**89**

Which of the following points has a distance of 10 from the point (−1, 2) ?(1 point)

Responses

(−1, −12)
Left Parenthesis negative 1 comma negative 12 Right Parenthesis

(−11, 2)
Left Parenthesis negative 11 comma 2 Right Parenthesis

(−1, 10)
Left Parenthesis negative 1 comma 10 Right Parenthesis

(10, 2)

To determine which point has a distance of 10 from the point \((-1, 2)\), we will use the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

In this case, we want the distance \(d\) to be 10, where \((x_1, y_1) = (-1, 2)\). We will check each given point by substituting its coordinates into the distance formula.

1. **For the point \((-1, -12)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (-12 - 2)^2} = \sqrt{0 + (-14)^2} = \sqrt{196} = 14 \quad (\text{not } 10)
\]

2. **For the point \((-11, 2)\)**:
\[
d = \sqrt{((-11) - (-1))^2 + (2 - 2)^2} = \sqrt{(-10)^2 + 0} = \sqrt{100} = 10 \quad (\text{this is } 10)
\]

3. **For the point \((-1, 10)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (10 - 2)^2} = \sqrt{0 + (8)^2} = \sqrt{64} = 8 \quad (\text{not } 10)
\]

4. **For the point \((10, 2)\)**:
\[
d = \sqrt{(10 - (-1))^2 + (2 - 2)^2} = \sqrt{(11)^2 + 0} = \sqrt{121} = 11 \quad (\text{not } 10)
\]

Therefore, the only point that has a distance of 10 from \((-1, 2)\) is:

**\((-11, 2)\)**.

1 and 2 are incorrect, the correct answers for 1) is idk lol sorry

It seems there might have been a misunderstanding about the distances in my previous response. Let's clarify the calculations for each of the points again step-by-step to verify the correct one has a distance of 10 from the point \((-1, 2)\).

### Given Points to Consider
1. \((-1, -12)\)
2. \((-11, 2)\)
3. \((-1, 10)\)
4. \((10, 2)\)

### Point Calculations

1. **For \((-1, -12)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (-12 - 2)^2} = \sqrt{0 + (-14)^2} = \sqrt{196} = 14
\]

2. **For \((-11, 2)\)**:
\[
d = \sqrt{((-11) - (-1))^2 + (2 - 2)^2} = \sqrt{(-10)^2 + 0} = \sqrt{100} = 10
\]

3. **For \((-1, 10)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (10 - 2)^2} = \sqrt{0 + 8^2} = \sqrt{64} = 8
\]

4. **For \((10, 2)\)**:
\[
d = \sqrt{((10) - (-1))^2 + (2 - 2)^2} = \sqrt{(11)^2 + 0} = \sqrt{121} = 11
\]

### Conclusion
From the calculations above:

- \((-1, -12)\) is **14**
- \((-11, 2)\) is **10**
- \((-1, 10)\) is **8**
- \((10, 2)\) is **11**

Thus, the point that has a distance of 10 from \((-1, 2)\) is indeed:

**\((-11, 2)\)**

If there was a different interpretation or specific context that led to the initial confusion, please clarify, and I'm happy to assist further!