Question

Use the image to answer the question.



A coordinate plane has an x-axis and y-axis both ranging from negative 7 to 7 in increments of 1. Points labeled with names of apples are plotted. Quadrant 1 is labeled with a left parenthesis positive sign comma positive sign right parenthesis. The Gala is plotted in quadrant 1. Gala is shown at 4 increments on the x-axis and 5 increments on the y-axis. Quadrant 2 is labeled with left parenthesis negative sign comma positive sign right parenthesis. Fuji is plotted in quadrant 2. Fuji is shown at 3 increments on the x-axis and 2 increments on the y-axis. Quadrant 3 is labeled with left parenthesis negative sign comma negative sign right parenthesis. Granny Smith is plotted in Quadrant 3. Granny Smith is shown at 4 increments on the x-axis and 4 increments on the y-axis. Quadrant 4 is labeled with left parenthesis positive sign comma negative sign right parenthesis. Pink Lady is plotted in quadrant 4. Pink Lady is shown at 3 increments on the x-axis and 3 increments on the y-axis.
Terrence is visiting an apple farm to pick apples. Use the graph to help him locate the Fuji apples.

(1 point)
Responses

1. (2, 3)
Left Parenthesis 2 comma 3 Right Parenthesis

2. (2, −3)
Left Parenthesis 2 comma negative 3 Right Parenthesis

3. (3, 2)
Left Parenthesis 3 comma 2 Right Parenthesis

4. (−3, 2)
Left Parenthesis negative 3 comma 2 Right Parenthesis
and Granny Smith, and Pink lady are in the negtive section, along with quadrent 3 and 4

Answer 1

Solve the following problem:

What is the distance from (−13, 12) to (−13, −77) ?

(1 point)
Responses

65
65

26
26

89
89

−89

Answer 2

Which of the following points has a distance of 10 from the point (−1, 2) ?(1 point)
Responses

(−1, −12)
Left Parenthesis negative 1 comma negative 12 Right Parenthesis

(−11, 2)
Left Parenthesis negative 11 comma 2 Right Parenthesis

(−1, 10)
Left Parenthesis negative 1 comma 10 Right Parenthesis

(10, 2)

Answer 3

1 and 2 are incorrect, the correct answers for 1) is idk lol sorry

Answer 4

To locate the Fuji apples, we look for the coordinates of Fuji, which is plotted in Quadrant 2. According to your description, Fuji is shown at 3 increments on the x-axis (which is negative in Quadrant 2) and 2 increments on the y-axis (which is positive in Quadrant 2).

Thus, the coordinates for Fuji are:

**(−3, 2)**

So the correct response for locating the Fuji apples is:

**4. (−3, 2)**

Answer 5

To find the distance between the points \((-13, 12)\) and \((-13, -77)\), we can use the distance formula. However, since both points have the same x-coordinate, the distance between them is simply the difference in their y-coordinates.

The distance \(d\) can be calculated as:

\[
d = |y_2 - y_1| = |-77 - 12| = |-89| = 89
\]

Thus, the distance from \((-13, 12)\) to \((-13, -77)\) is:

**89**

Answer 6

To determine which point has a distance of 10 from the point \((-1, 2)\), we will use the distance formula:

\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

In this case, we want the distance \(d\) to be 10, where \((x_1, y_1) = (-1, 2)\). We will check each given point by substituting its coordinates into the distance formula.

1. **For the point \((-1, -12)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (-12 - 2)^2} = \sqrt{0 + (-14)^2} = \sqrt{196} = 14 \quad (\text{not } 10)
\]

2. **For the point \((-11, 2)\)**:
\[
d = \sqrt{((-11) - (-1))^2 + (2 - 2)^2} = \sqrt{(-10)^2 + 0} = \sqrt{100} = 10 \quad (\text{this is } 10)
\]

3. **For the point \((-1, 10)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (10 - 2)^2} = \sqrt{0 + (8)^2} = \sqrt{64} = 8 \quad (\text{not } 10)
\]

4. **For the point \((10, 2)\)**:
\[
d = \sqrt{(10 - (-1))^2 + (2 - 2)^2} = \sqrt{(11)^2 + 0} = \sqrt{121} = 11 \quad (\text{not } 10)
\]

Therefore, the only point that has a distance of 10 from \((-1, 2)\) is:

**\((-11, 2)\)**.

Answer 7

It seems there might have been a misunderstanding about the distances in my previous response. Let's clarify the calculations for each of the points again step-by-step to verify the correct one has a distance of 10 from the point \((-1, 2)\).

### Given Points to Consider
1. \((-1, -12)\)
2. \((-11, 2)\)
3. \((-1, 10)\)
4. \((10, 2)\)

### Point Calculations

1. **For \((-1, -12)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (-12 - 2)^2} = \sqrt{0 + (-14)^2} = \sqrt{196} = 14
\]

2. **For \((-11, 2)\)**:
\[
d = \sqrt{((-11) - (-1))^2 + (2 - 2)^2} = \sqrt{(-10)^2 + 0} = \sqrt{100} = 10
\]

3. **For \((-1, 10)\)**:
\[
d = \sqrt{((-1) - (-1))^2 + (10 - 2)^2} = \sqrt{0 + 8^2} = \sqrt{64} = 8
\]

4. **For \((10, 2)\)**:
\[
d = \sqrt{((10) - (-1))^2 + (2 - 2)^2} = \sqrt{(11)^2 + 0} = \sqrt{121} = 11
\]

### Conclusion
From the calculations above:

- \((-1, -12)\) is **14**
- \((-11, 2)\) is **10**
- \((-1, 10)\) is **8**
- \((10, 2)\) is **11**

Thus, the point that has a distance of 10 from \((-1, 2)\) is indeed:

**\((-11, 2)\)**

If there was a different interpretation or specific context that led to the initial confusion, please clarify, and I'm happy to assist further!