Responses
(x+8)(x−4)=0
left parenthesis x plus 8 right parenthesis left parenthesis x minus 4 right parenthesis equals 0
(x−4)(x−8)=0
left parenthesis x minus 4 right parenthesis left parenthesis x minus 8 right parenthesis equals 0
(x+4)(x−8)=0
left parenthesis x plus 4 right parenthesis left parenthesis x minus 8 right parenthesis equals 0
(x+4)(x+8)=0
left parenthesis x plus 4 right parenthesis left parenthesis x plus 8 right parenthesis equals 0
1 answer
To factor the quadratic equation \(x^2 + 4x - 32 = 0\), we need to find two numbers that multiply to \(-32\) (the constant term) and add up to \(4\) (the coefficient of the linear term).
The two numbers that satisfy these conditions are \(8\) and \(-4\). Therefore, we can write the quadratic in its factored form:
\[ (x + 8)(x - 4) = 0 \]
So, the correct answer is:
\((x+8)(x−4)=0\)
