To factor the quadratic equation \(x^2 + 10x + 16 = 0\), we need to find two numbers that add up to 10 (the coefficient of \(x\)) and multiply to 16 (the constant term).
The numbers that meet these criteria are 2 and 8, since:
- \(2 + 8 = 10\)
- \(2 \times 8 = 16\)
Now, we can write the factored form of the equation:
\[ (x + 2)(x + 8) = 0 \]
So the lesser number is 2 and the greater number is 8.
Final answer: \((x + 2)(x + 8) = 0\)