A university football stadium has 81,500 seats. The stadium is at full capacity on game day. Layla believes only 79,000 seats are occupied. Find the percent error of Layla’s prediction. Round your answer to the nearest hundredth of a percent.(1 point)

Question

Responses

90.3067%
90.3067%

−3.07%
negative 3.07 percent

0.0307%
0.0307%

3.07%
3.07%

Answer 1

To find the percent error of Layla's prediction, you can use the formula for percent error:

\[ \text{Percent Error} = \left( \frac{\text{Actual Value} - \text{Predicted Value}}{\text{Actual Value}} \right) \times 100 \]

In this case:

• Actual Value = 81,500 (the number of seats at full capacity)
• Predicted Value = 79,000 (Layla's belief)

Now, plug in the values:

\[ \text{Percent Error} = \left( \frac{81,500 - 79,000}{81,500} \right) \times 100 \]

First, calculate the difference:

\[ 81,500 - 79,000 = 2,500 \]

Next, divide by the actual value:

\[ \frac{2,500}{81,500} \approx 0.0307 \]

Finally, multiply by 100 to convert to a percentage:

\[ 0.0307 \times 100 \approx 3.07% \]

Thus, the percent error of Layla’s prediction is 3.07%.

The correct response is:

3.07%.