Question

Jazmin is 5 years older that her brother carl. Lucas is twice as old as carl. The sum of their age is 47. How old is each person

Answer 1

Let Carl's age be \( x \). Then, Jazmin's age is \( x + 5 \) (since she is 5 years older than Carl). Lucas's age is \( 2x \) (since he is twice as old as Carl).

The sum of their ages can be expressed as:

\[
x + (x + 5) + 2x = 47
\]

Now, simplify the equation:

\[
x + x + 5 + 2x = 47
\]
\[
4x + 5 = 47
\]

Subtract 5 from both sides:

\[
4x = 42
\]

Now, divide by 4:

\[
x = 10.5
\]

Now we can find the ages of each person:

- Carl's age: \( x = 10.5 \)
- Jazmin's age: \( x + 5 = 10.5 + 5 = 15.5 \)
- Lucas's age: \( 2x = 2 \times 10.5 = 21 \)

So, the ages are:

- Carl: 10.5 years
- Jazmin: 15.5 years
- Lucas: 21 years