Using the quadratic formula, find the solution to 3x2+18x+24=0 .(1 point)

To solve the quadratic equation \(3x^2 + 18x + 24 = 0\) using the quadratic formula, we first identify the coefficients:

- \(a = 3\)
- \(b = 18\)
- \(c = 24\)

The quadratic formula is given by:

\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]

Now, we calculate the discriminant:

\[
b^2 - 4ac = 18^2 - 4 \times 3 \times 24 = 324 - 288 = 36
\]

Next, we apply the quadratic formula:

\[
x = \frac{-18 \pm \sqrt{36}}{2 \times 3}
\]

Calculating \(\sqrt{36}\):

\[
\sqrt{36} = 6
\]

Now substitute back into the formula:

\[
x = \frac{-18 \pm 6}{6}
\]

This gives us two possible solutions:

1.

\[
x = \frac{-18 + 6}{6} = \frac{-12}{6} = -2
\]

2.

\[
x = \frac{-18 - 6}{6} = \frac{-24}{6} = -4
\]

Therefore, the solutions are:

\[
x = -2 \quad \text{and} \quad x = -4
\]

So the final answer is:

**x = −2, x = −4**.