Question
Solve the equation. Simplify all irrational solutions.
x2 − 6x − 23 = 0
(1 point)
Responses
x = {4±32–√}
x = {4±32–√}
x = {3±42–√}
x = {3±42–√}
x = {±32−−√}
x = {±32−−√}
x = {−3±42–√}
x2 − 6x − 23 = 0
(1 point)
Responses
x = {4±32–√}
x = {4±32–√}
x = {3±42–√}
x = {3±42–√}
x = {±32−−√}
x = {±32−−√}
x = {−3±42–√}
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the equation \(x^2 - 6x - 23 = 0\), we can apply the quadratic formula:
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In this equation:
- \(a = 1\)
- \(b = -6\)
- \(c = -23\)
Now, we can plug these values into the quadratic formula.
First, calculate the discriminant \(b^2 - 4ac\):
\[
b^2 = (-6)^2 = 36
\]
\[
4ac = 4 \cdot 1 \cdot (-23) = -92
\]
Now, calculate \(b^2 - 4ac\):
\[
b^2 - 4ac = 36 - (-92) = 36 + 92 = 128
\]
So now we can substitute these values back into the formula:
\[
x = \frac{6 \pm \sqrt{128}}{2}
\]
Next, simplify \(\sqrt{128}\):
\[
\sqrt{128} = \sqrt{64 \cdot 2} = 8\sqrt{2}
\]
Now substituting back:
\[
x = \frac{6 \pm 8\sqrt{2}}{2}
\]
Now simplify this expression:
\[
x = \frac{6}{2} \pm \frac{8\sqrt{2}}{2}
\]
\[
x = 3 \pm 4\sqrt{2}
\]
Finally, we can write the solution as:
\[
x = \{3 \pm 4\sqrt{2}\}
\]
So the correct response from the options given is:
\(x = \{3 \pm 4\sqrt{2}\}\).
\[
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
\]
In this equation:
- \(a = 1\)
- \(b = -6\)
- \(c = -23\)
Now, we can plug these values into the quadratic formula.
First, calculate the discriminant \(b^2 - 4ac\):
\[
b^2 = (-6)^2 = 36
\]
\[
4ac = 4 \cdot 1 \cdot (-23) = -92
\]
Now, calculate \(b^2 - 4ac\):
\[
b^2 - 4ac = 36 - (-92) = 36 + 92 = 128
\]
So now we can substitute these values back into the formula:
\[
x = \frac{6 \pm \sqrt{128}}{2}
\]
Next, simplify \(\sqrt{128}\):
\[
\sqrt{128} = \sqrt{64 \cdot 2} = 8\sqrt{2}
\]
Now substituting back:
\[
x = \frac{6 \pm 8\sqrt{2}}{2}
\]
Now simplify this expression:
\[
x = \frac{6}{2} \pm \frac{8\sqrt{2}}{2}
\]
\[
x = 3 \pm 4\sqrt{2}
\]
Finally, we can write the solution as:
\[
x = \{3 \pm 4\sqrt{2}\}
\]
So the correct response from the options given is:
\(x = \{3 \pm 4\sqrt{2}\}\).
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