To solve the equation \(0 = 2x^2 - 5x - 3\) algebraically, we will use the quadratic formula, which is given by:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
In your equation, the coefficients are:
- \(a = 2\)
- \(b = -5\)
- \(c = -3\)
- First, we need to calculate the discriminant \(b^2 - 4ac\):
\[ b^2 - 4ac = (-5)^2 - 4(2)(-3) = 25 + 24 = 49 \]
- Now we can substitute \(a\), \(b\), and the discriminant into the quadratic formula:
\[ x = \frac{-(-5) \pm \sqrt{49}}{2 \cdot 2} \]
This simplifies to:
\[ x = \frac{5 \pm 7}{4} \]
- Now we will calculate the two potential solutions:
Solution 1:
\[ x = \frac{5 + 7}{4} = \frac{12}{4} = 3 \]
Solution 2:
\[ x = \frac{5 - 7}{4} = \frac{-2}{4} = -\frac{1}{2} \]
Thus, the solutions to the equation \(0 = 2x^2 - 5x - 3\) are:
\[ x = -\frac{1}{2}, \quad x = 3 \]
Therefore, the correct response is:
x equals negative Start Fraction 1 over 2 End Fraction , x equals 3.