The pulling force component along the direction of motion is 60 cos42 = 44.6 N
Subtract 15N (backwards friction) from that to get the net force, F.
Then use F = m a = (W/g)*a
to solve for the acceleration, a.
You have use W/g for the mass because they gave you the weight of the box (W), not the mass (m).
m = 12.76 kg
a = 29.6 N/12.76 kg = ___ m/s^2
a 125Newton box is pulled east along a horizontal surface with a force of 60Newton acting at an angle of 42degrees. if the force of friction on the box is 15 newton, what is the acceleration?
1 answer
1 answer