Chargaff's rules state that in a double-stranded DNA molecule, the amount of adenine (A) is equal to the amount of thymine (T), and the amount of cytosine (C) is equal to the amount of guanine (G).
Given that adenine (A) measures approximately 29% in salmon DNA, you can deduce the following:
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Thymine (T): Since A = T, thymine will also be 29%.
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Cytosine (C) and Guanine (G): The total of A, T, C, and G must equal 100%. Therefore, if both A and T are 29%, then:
\[ A + T + C + G = 100% \] \[ 29% + 29% + C + G = 100% \] \[ 58% + C + G = 100% \] \[ C + G = 42% \]
Since C = G (due to Chargaff's rules), you can say that:
\[ C = G = \frac{42%}{2} = 21% \]
So, for salmon DNA:
- Thymine (T) is 29%
- Guanine (G) is 21%
- Cytosine (C) is 21%
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