Question
Rationalize the denominator.
StartFraction 5 Over StartRoot 5 EndRoot plus 2 EndFraction
Question content area bottom
Part 1
StartFraction 5 Over StartRoot 5 EndRoot plus 2 EndFraction
equals
enter your response here
(Type an exact answer, using radicals as needed. Simplify your answer. Rationalize all denominators.)
StartFraction 5 Over StartRoot 5 EndRoot plus 2 EndFraction
Question content area bottom
Part 1
StartFraction 5 Over StartRoot 5 EndRoot plus 2 EndFraction
equals
enter your response here
(Type an exact answer, using radicals as needed. Simplify your answer. Rationalize all denominators.)
Answers
GPT-4o mini
To rationalize the denominator of the expression
\[
\frac{5}{\sqrt{5} + 2},
\]
we can multiply the numerator and denominator by the conjugate of the denominator, which is \(\sqrt{5} - 2\). This technique eliminates the square root in the denominator.
Let's perform the calculation step-by-step:
1. **Multiply the numerator and denominator by the conjugate**:
\[
\frac{5}{\sqrt{5} + 2} \cdot \frac{\sqrt{5} - 2}{\sqrt{5} - 2} = \frac{5(\sqrt{5} - 2)}{(\sqrt{5} + 2)(\sqrt{5} - 2)}.
\]
2. **Calculate the denominator using the difference of squares**:
\[
(\sqrt{5} + 2)(\sqrt{5} - 2) = (\sqrt{5})^2 - (2)^2 = 5 - 4 = 1.
\]
3. **Rewrite the expression**:
Now we have:
\[
\frac{5(\sqrt{5} - 2)}{1} = 5(\sqrt{5} - 2).
\]
4. **Distributing the numerator**:
Distributing gives:
\[
5\sqrt{5} - 10.
\]
Thus, the rationalized form of the original expression \(\frac{5}{\sqrt{5} + 2}\) is:
\[
5\sqrt{5} - 10.
\]
So the final answer is:
\[
\boxed{5\sqrt{5} - 10}.
\]
\[
\frac{5}{\sqrt{5} + 2},
\]
we can multiply the numerator and denominator by the conjugate of the denominator, which is \(\sqrt{5} - 2\). This technique eliminates the square root in the denominator.
Let's perform the calculation step-by-step:
1. **Multiply the numerator and denominator by the conjugate**:
\[
\frac{5}{\sqrt{5} + 2} \cdot \frac{\sqrt{5} - 2}{\sqrt{5} - 2} = \frac{5(\sqrt{5} - 2)}{(\sqrt{5} + 2)(\sqrt{5} - 2)}.
\]
2. **Calculate the denominator using the difference of squares**:
\[
(\sqrt{5} + 2)(\sqrt{5} - 2) = (\sqrt{5})^2 - (2)^2 = 5 - 4 = 1.
\]
3. **Rewrite the expression**:
Now we have:
\[
\frac{5(\sqrt{5} - 2)}{1} = 5(\sqrt{5} - 2).
\]
4. **Distributing the numerator**:
Distributing gives:
\[
5\sqrt{5} - 10.
\]
Thus, the rationalized form of the original expression \(\frac{5}{\sqrt{5} + 2}\) is:
\[
5\sqrt{5} - 10.
\]
So the final answer is:
\[
\boxed{5\sqrt{5} - 10}.
\]