To solve the quadratic equation \((x + 27)^2 - 6 = -3\), we will first simplify it step by step.
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Isolate the squared term: \[ (x + 27)^2 - 6 = -3 \] Adding 6 to both sides: \[ (x + 27)^2 = 3 \]
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Take the square root of both sides: \[ x + 27 = \pm \sqrt{3} \]
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Isolate \(x\): \[ x = -27 \pm \sqrt{3} \]
Now we can find the two solutions:
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Calculate the two solutions:
- First solution (smallest): \[ x = -27 - \sqrt{3} \]
- Second solution (largest): \[ x = -27 + \sqrt{3} \]
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Use a calculator to find \(\sqrt{3}\): \[ \sqrt{3} \approx 1.732 \]
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Calculate the first solution: \[ x_1 = -27 - 1.732 \approx -28.732 \]
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Calculate the second solution: \[ x_2 = -27 + 1.732 \approx -25.268 \]
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Round to the nearest hundredth:
- First solution: \(x_1 \approx -28.73\)
- Second solution: \(x_2 \approx -25.27\)
Now, listing the solutions from smallest to largest:
- The first solution is \(x \approx -28.73\).
- The second solution is \(x \approx -25.27\).
Final Answers:
- The first solution is \(x = -28.73\)
- The second solution is \(x = -25.27\)