acceleration = (Net horizontal force)/Mass
= (320 cos 17 - M g *0.27)/M
= 306/M -0.27 g = (4.86 - 2.65)
= 2.21 m/s^2
Physics force of friction question
a 63kg water skier is pulled across a lake by a rope that exerts a force of 3.2x10^2 and makes an angle 17 degrees above the horizontal. if the coefficient between the skies and the lake is 0.27 at what rate will the skier accelerate?
1 answer