Question
Use the information and table to answer the following question.
A student is using a sound machine to produce sound wave X and sound wave Y.
Sound Wave
Wavelength (m)
Frequency (Hz)
Amplitude (dB)
X
1.5
230
25
Y
2.5
140
50
How could the student manipulate the sounds to make them match in volume but make sound wave X higher pitch than sound wave Y?
Question 13 options:
Sound wave X and sound wave Y should have the same frequency, but sound wave X should have a higher amplitude than sound wave Y.
Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher frequency than sound wave Y.
Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher wavelength than sound wave Y.
Sound wave X and sound wave Y should have the same frequency, but sound wave X should have a lower wavelength than sound wave Y.
A student is using a sound machine to produce sound wave X and sound wave Y.
Sound Wave
Wavelength (m)
Frequency (Hz)
Amplitude (dB)
X
1.5
230
25
Y
2.5
140
50
How could the student manipulate the sounds to make them match in volume but make sound wave X higher pitch than sound wave Y?
Question 13 options:
Sound wave X and sound wave Y should have the same frequency, but sound wave X should have a higher amplitude than sound wave Y.
Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher frequency than sound wave Y.
Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher wavelength than sound wave Y.
Sound wave X and sound wave Y should have the same frequency, but sound wave X should have a lower wavelength than sound wave Y.
Answers
GPT-4o mini
To answer this question, we need to understand the relationships between wavelength, frequency, amplitude, and perceived volume and pitch of sound waves.
1. **Pitch** is determined by frequency: Higher frequency means higher pitch.
2. **Volume** (loudness) is generally influenced by amplitude: Higher amplitude means louder sound.
From the information given:
- Sound wave X has a frequency of 230 Hz and an amplitude of 25 dB.
- Sound wave Y has a frequency of 140 Hz and an amplitude of 50 dB.
To achieve the goal of having sound wave X at a higher pitch than sound wave Y while matching them in volume, the following conditions must be satisfied:
1. **Sound wave X must have a higher frequency than sound wave Y** to ensure it is higher in pitch. Since X (230 Hz) is already higher than Y (140 Hz), this condition is satisfied.
2. **Sound wave X and sound wave Y should have the same amplitude (loudness)** so that they match in volume.
Given this analysis, the correct option is:
**Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher frequency than sound wave Y.**
1. **Pitch** is determined by frequency: Higher frequency means higher pitch.
2. **Volume** (loudness) is generally influenced by amplitude: Higher amplitude means louder sound.
From the information given:
- Sound wave X has a frequency of 230 Hz and an amplitude of 25 dB.
- Sound wave Y has a frequency of 140 Hz and an amplitude of 50 dB.
To achieve the goal of having sound wave X at a higher pitch than sound wave Y while matching them in volume, the following conditions must be satisfied:
1. **Sound wave X must have a higher frequency than sound wave Y** to ensure it is higher in pitch. Since X (230 Hz) is already higher than Y (140 Hz), this condition is satisfied.
2. **Sound wave X and sound wave Y should have the same amplitude (loudness)** so that they match in volume.
Given this analysis, the correct option is:
**Sound wave X and sound wave Y should have the same amplitude, but sound wave X should have a higher frequency than sound wave Y.**
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