Question

find the critical no's/ points in
(X^-2)(lnx)

Answer 1

let y = (x^-2)lnx
dy/dx = lnx(-2x^-3) + x^-2(1/x)
= -2lnx/x^3 + 1/x^3 = 0 for max/min of y

multiply by x^3
2lnx = 1
lnx = 1/2
x = e^(1/2) or √e

then y = ln(√e)/e = 1/(2e)

critical point is (√e, 1/(2e))

Answer 2

hey thnxx but web assign is not accepting this ans, i dunno why it says that its wrong.

Answer 3

try e^(1/2) instead of √e or find the decimals

the above point in rounded decimals is
(1.6487, .1839)

Answer 4

its wrong again :(