To determine the number of primary and secondary turns of the transformer, we will use the transformer equations and the given parameters.
Step 1: Calculate the Maximum Magnetic Flux (Φ)
The formula for the maximum magnetic flux (Φ) is:
\[ Φ = B_{max} \cdot A \]
Where:
- \( B_{max} \) is the maximum flux density (1.5 Wb/m²)
- \( A \) is the cross-sectional area of the core (0.008 m²)
Substituting the values:
\[ Φ = 1.5 , \text{Wb/m²} \cdot 0.008 , \text{m²} = 0.012 , \text{Wb} \]
Step 2: Calculate the Effective (True) Flux (Φ_eff)
The effective flux can be calculated as:
\[ Φ_{eff} = Φ \cdot \text{stacking factor} \]
Substituting the stacking factor of 0.93:
\[ Φ_{eff} = 0.012 , \text{Wb} \cdot 0.93 \approx 0.01116 , \text{Wb} \]
Step 3: Calculate the Number of Turns
The number of turns (N) is related to the voltage, frequency, and effective flux as follows:
\[ N = \frac{V}{4.44 \cdot f \cdot Φ_{eff}} \]
Where:
- \( V \) is the voltage (in this case, we will calculate both primary and secondary voltages)
- \( f \) is the frequency (50 Hz)
- \( Φ_{eff} \) is the effective flux (0.01116 Wb)
For Primary Turns:
Given:
- Primary Voltage \( V_p = 1100 , \text{V} \)
Calculating the number of primary turns:
\[ N_p = \frac{1100}{4.44 \cdot 50 \cdot 0.01116} \]
Calculating the denominator:
\[ 4.44 \cdot 50 \approx 222 \] \[ 222 \cdot 0.01116 \approx 2.48 \]
Now substituting back:
\[ N_p \approx \frac{1100}{2.48} \approx 442.74 \approx 443 \text{ turns} \]
For Secondary Turns:
Given:
- Secondary Voltage \( V_s = 240 , \text{V} \)
Calculating the number of secondary turns:
\[ N_s = \frac{240}{4.44 \cdot 50 \cdot 0.01116} \]
Using the previous calculation for the denominator:
\[ N_s \approx \frac{240}{2.48} \approx 96.77 \approx 97 \text{ turns} \]
Conclusion:
The number of turns for the transformer is approximately:
- Primary Turns (N_p): 443 turns
- Secondary Turns (N_s): 97 turns