Question
A rectangular section of wilderness will be set aside as a new wildlife refuge. Its dimensions are 6 × 103%0D%0A6%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A3%0D%0A meters by 3 × 104%0D%0A3%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A4%0D%0A meters. Find the area of the land in square meters. Put your answer in scientific notation.%0D%0A%0D%0AShow your work.%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A90 × 108%0D%0A90%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A8%0D%0A90 × 108%0D%0A90%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A8%0D%0A%0D%0A18 × 107%0D%0A18%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A7%0D%0A18 × 107%0D%0A18%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A7%0D%0A%0D%0A9.0 × 109%0D%0A9.0%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A9%0D%0A9.0 × 109%0D%0A9.0%0D%0A %0D%0A×%0D%0A %0D%0A10%0D%0A9%0D%0A%0D%0A1.8 × 108
Answers
GPT-4o mini
To find the area of the rectangular section of wilderness, we can use the formula for the area of a rectangle:
\[
\text{Area} = \text{length} \times \text{width}
\]
Given the dimensions in scientific notation:
- Length: \( 6 \times 10^3 \) meters
- Width: \( 3 \times 10^4 \) meters
Now, we can calculate the area:
\[
\text{Area} = (6 \times 10^3) \times (3 \times 10^4)
\]
Using the associative property of multiplication, we can rearrange the multiplication:
\[
\text{Area} = (6 \times 3) \times (10^3 \times 10^4)
\]
Calculating the numerical part:
\[
6 \times 3 = 18
\]
For the powers of 10:
\[
10^3 \times 10^4 = 10^{3+4} = 10^7
\]
Now, combining both parts, we get:
\[
\text{Area} = 18 \times 10^7
\]
Now, we can convert \( 18 \) into scientific notation:
\[
18 = 1.8 \times 10^1
\]
Substituting this back into the area calculation gives us:
\[
\text{Area} = (1.8 \times 10^1) \times 10^7
\]
Using the property of exponents:
\[
\text{Area} = 1.8 \times 10^{1+7} = 1.8 \times 10^8
\]
Thus, the area of the land in square meters, in scientific notation, is:
\[
\boxed{1.8 \times 10^8}
\]
\[
\text{Area} = \text{length} \times \text{width}
\]
Given the dimensions in scientific notation:
- Length: \( 6 \times 10^3 \) meters
- Width: \( 3 \times 10^4 \) meters
Now, we can calculate the area:
\[
\text{Area} = (6 \times 10^3) \times (3 \times 10^4)
\]
Using the associative property of multiplication, we can rearrange the multiplication:
\[
\text{Area} = (6 \times 3) \times (10^3 \times 10^4)
\]
Calculating the numerical part:
\[
6 \times 3 = 18
\]
For the powers of 10:
\[
10^3 \times 10^4 = 10^{3+4} = 10^7
\]
Now, combining both parts, we get:
\[
\text{Area} = 18 \times 10^7
\]
Now, we can convert \( 18 \) into scientific notation:
\[
18 = 1.8 \times 10^1
\]
Substituting this back into the area calculation gives us:
\[
\text{Area} = (1.8 \times 10^1) \times 10^7
\]
Using the property of exponents:
\[
\text{Area} = 1.8 \times 10^{1+7} = 1.8 \times 10^8
\]
Thus, the area of the land in square meters, in scientific notation, is:
\[
\boxed{1.8 \times 10^8}
\]
no words
GPT-4o mini
\[
\text{Length} = 6 \times 10^3 \, \text{m}
\]
\[
\text{Width} = 3 \times 10^4 \, \text{m}
\]
\[
\text{Area} = (6 \times 10^3) \times (3 \times 10^4)
\]
\[
= (6 \times 3) \times (10^3 \times 10^4)
\]
\[
= 18 \times 10^{3+4}
\]
\[
= 18 \times 10^7
\]
\[
= 1.8 \times 10^1 \times 10^7
\]
\[
= 1.8 \times 10^{8}
\]
\[
\text{Area} = \boxed{1.8 \times 10^8} \, \text{m}^2
\]
\text{Length} = 6 \times 10^3 \, \text{m}
\]
\[
\text{Width} = 3 \times 10^4 \, \text{m}
\]
\[
\text{Area} = (6 \times 10^3) \times (3 \times 10^4)
\]
\[
= (6 \times 3) \times (10^3 \times 10^4)
\]
\[
= 18 \times 10^{3+4}
\]
\[
= 18 \times 10^7
\]
\[
= 1.8 \times 10^1 \times 10^7
\]
\[
= 1.8 \times 10^{8}
\]
\[
\text{Area} = \boxed{1.8 \times 10^8} \, \text{m}^2
\]
less
GPT-4o mini
\[
\text{Area} = (6 \times 10^3) \times (3 \times 10^4) = 18 \times 10^7 = 1.8 \times 10^8 \, \text{m}^2
\]
\[
\text{Answer: } \boxed{1.8 \times 10^8}
\]
\text{Area} = (6 \times 10^3) \times (3 \times 10^4) = 18 \times 10^7 = 1.8 \times 10^8 \, \text{m}^2
\]
\[
\text{Answer: } \boxed{1.8 \times 10^8}
\]