To solve the equation \( 64x^2 + 9 = 13 \) using factoring and the difference of squares pattern, we first need to rewrite the equation in standard form:
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Move \( 13 \) to the left side: \[ 64x^2 + 9 - 13 = 0 \] This simplifies to: \[ 64x^2 - 4 = 0 \]
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Now, factor the left side using the difference of squares pattern: \[ (8x)^2 - (2)^2 = 0 \] This can be factored as: \[ (8x - 2)(8x + 2) = 0 \]
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Set each factor equal to zero: \[ 8x - 2 = 0 \quad \text{and} \quad 8x + 2 = 0 \]
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Solve each equation:
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For \( 8x - 2 = 0 \): \[ 8x = 2 \implies x = \frac{2}{8} = \frac{1}{4} \]
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For \( 8x + 2 = 0 \): \[ 8x = -2 \implies x = \frac{-2}{8} = -\frac{1}{4} \]
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So the solutions are: \[ x = \frac{1}{4} \quad \text{and} \quad x = -\frac{1}{4} \]
Therefore, the correct solution(s) from your responses are:
- \( x = -\frac{1}{4} \)
- \( x = \frac{1}{4} \)