Question
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
The figure must be an isosceles trapezoid because it has 2 congruent base angles.
The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
The figure could be a rhombus because the 2 lines of symmetry bisect the angles.
The figure could be a square because the diagonals of a square bisect the right angles.
The figure must be an isosceles trapezoid because it has 2 congruent base angles.
The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.
The figure could be a rhombus because the 2 lines of symmetry bisect the angles.
The figure could be a square because the diagonals of a square bisect the right angles.
Answers
GPT-4o mini
To evaluate the given statements, we start by recognizing that a quadrilateral with exactly 2 lines of symmetry that are both angle bisectors typically has a certain shape.
1. **The figure must be an isosceles trapezoid because it has 2 congruent base angles.**
- This statement is true in the sense that an isosceles trapezoid has a line of symmetry along the vertical line that bisects the bases and the angles at the top and bottom. It can have 2 lines of symmetry if we consider the angle bisectors as the lines that bisect the top and bottom angles, leading to the conclusion that it could be an isosceles trapezoid; however, it is not definitive that this is the only shape.
2. **The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.**
- This statement is false; while rectangles do have lines of symmetry, they also have 4 lines of symmetry (two vertical and two horizontal). Therefore, a rectangle does not fit the criteria of having exactly 2 lines of symmetry.
3. **The figure could be a rhombus because the 2 lines of symmetry bisect the angles.**
- A rhombus does have 2 lines of symmetry that are the diagonals, and they indeed bisect the angles. Therefore, a rhombus fits this description.
4. **The figure could be a square because the diagonals of a square bisect the right angles.**
- A square is a specific type of rhombus, and it does have 4 lines of symmetry (two diagonals and two midlines). Thus, while this statement is true about a square having diagonals that bisect angles, it does not fit the criteria of having exactly 2 lines of symmetry.
From our evaluations, the best fitting statement that satisfies the criteria of having exactly 2 lines of symmetry (which are angle bisectors) is:
**The figure could be a rhombus because the 2 lines of symmetry bisect the angles.**
Thus, the true statement is that the figure could be a rhombus.
1. **The figure must be an isosceles trapezoid because it has 2 congruent base angles.**
- This statement is true in the sense that an isosceles trapezoid has a line of symmetry along the vertical line that bisects the bases and the angles at the top and bottom. It can have 2 lines of symmetry if we consider the angle bisectors as the lines that bisect the top and bottom angles, leading to the conclusion that it could be an isosceles trapezoid; however, it is not definitive that this is the only shape.
2. **The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry.**
- This statement is false; while rectangles do have lines of symmetry, they also have 4 lines of symmetry (two vertical and two horizontal). Therefore, a rectangle does not fit the criteria of having exactly 2 lines of symmetry.
3. **The figure could be a rhombus because the 2 lines of symmetry bisect the angles.**
- A rhombus does have 2 lines of symmetry that are the diagonals, and they indeed bisect the angles. Therefore, a rhombus fits this description.
4. **The figure could be a square because the diagonals of a square bisect the right angles.**
- A square is a specific type of rhombus, and it does have 4 lines of symmetry (two diagonals and two midlines). Thus, while this statement is true about a square having diagonals that bisect angles, it does not fit the criteria of having exactly 2 lines of symmetry.
From our evaluations, the best fitting statement that satisfies the criteria of having exactly 2 lines of symmetry (which are angle bisectors) is:
**The figure could be a rhombus because the 2 lines of symmetry bisect the angles.**
Thus, the true statement is that the figure could be a rhombus.
Related Questions
Which statement about this figure is true?
It has reflectional symmetry with 22 lines of symm...
Use the image to answer the question.
How many lines of symmetry does the following figure have?...
for a triangle list the respective names of the points of.
1. concurrency of perpendicular bisector...
Use the image to answer the question.
How many lines of symmetry does the following figure have?...