5+4/7(21+3x)=41

To solve the equation \( 5 + \frac{4}{7}(21 + 3x) = 41 \), follow these steps:

1. First, isolate the term with \( x \):
\[
\frac{4}{7}(21 + 3x) = 41 - 5
\]
\[
\frac{4}{7}(21 + 3x) = 36
\]

2. Next, eliminate the fraction by multiplying both sides by \( 7 \):
\[
4(21 + 3x) = 36 \times 7
\]
\[
4(21 + 3x) = 252
\]

3. Now divide both sides by \( 4 \):
\[
21 + 3x = \frac{252}{4}
\]
\[
21 + 3x = 63
\]

4. Subtract \( 21 \) from both sides:
\[
3x = 63 - 21
\]
\[
3x = 42
\]

5. Finally, divide by \( 3 \):
\[
x = \frac{42}{3}
\]
\[
x = 14
\]

So, the solution is \( x = 14 \).