To find the correct recursive function for the sequence \( 41, 29, 17, 5 \), let's first observe the pattern in the sequence.
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Initial terms:
- \( A_1 = 41 \)
- \( A_2 = 29 \)
- \( A_3 = 17 \)
- \( A_4 = 5 \)
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Differences:
- \( A_2 - A_1 = 29 - 41 = -12 \)
- \( A_3 - A_2 = 17 - 29 = -12 \)
- \( A_4 - A_3 = 5 - 17 = -12 \)
From the above calculations, we see that each term in the sequence is obtained by subtracting 12 from the previous term.
This leads to the following recursive formula: \[ A_n = A_{n-1} - 12 \quad \text{for } n \geq 2, \text{ with } A_1 = 41. \]
Thus, the answer is: \[ A_n = A_{n-1} - 12, \quad A_1 = 41. \]