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Rewrite the following quadratic equation in standard form and then solve by factoring out the GCF: 6x2=22x
.(1 point)
The smaller solution is x=
, and the larger solution is x=
.
Remaining Attempts : 3
.(1 point)
The smaller solution is x=
, and the larger solution is x=
.
Remaining Attempts : 3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To rewrite the equation \( 6x^2 = 22x \) in standard form, we'll first move all terms to one side of the equation.
Subtract \( 22x \) from both sides:
\[
6x^2 - 22x = 0
\]
Next, we can factor out the greatest common factor (GCF), which is \( 2x \):
\[
2x(3x - 11) = 0
\]
Now we can set each factor equal to zero:
1. \( 2x = 0 \)
2. \( 3x - 11 = 0 \)
From the first equation \( 2x = 0 \):
\[
x = 0
\]
From the second equation \( 3x - 11 = 0 \):
\[
3x = 11 \implies x = \frac{11}{3}
\]
So, the solutions are:
- The smaller solution is \( x = 0 \)
- The larger solution is \( x = \frac{11}{3} \)
Final answers:
The smaller solution is \( \mathbf{x = 0} \), and the larger solution is \( \mathbf{x = \frac{11}{3}} \).
Subtract \( 22x \) from both sides:
\[
6x^2 - 22x = 0
\]
Next, we can factor out the greatest common factor (GCF), which is \( 2x \):
\[
2x(3x - 11) = 0
\]
Now we can set each factor equal to zero:
1. \( 2x = 0 \)
2. \( 3x - 11 = 0 \)
From the first equation \( 2x = 0 \):
\[
x = 0
\]
From the second equation \( 3x - 11 = 0 \):
\[
3x = 11 \implies x = \frac{11}{3}
\]
So, the solutions are:
- The smaller solution is \( x = 0 \)
- The larger solution is \( x = \frac{11}{3} \)
Final answers:
The smaller solution is \( \mathbf{x = 0} \), and the larger solution is \( \mathbf{x = \frac{11}{3}} \).
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