To solve the equation \(-5x^2 - 8 = -6x\), we first rearrange it into standard form. We can do this by moving all terms to one side of the equation:
\[ -5x^2 + 6x - 8 = 0 \]
Next, we can multiply through by \(-1\) to make the leading coefficient positive:
\[ 5x^2 - 6x + 8 = 0 \]
Now we will use the quadratic formula to solve for \(x\), which is given by:
\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
In our equation, \(a = 5\), \(b = -6\), and \(c = 8\). First, we calculate the discriminant \(b^2 - 4ac\):
\[ b^2 = (-6)^2 = 36 \] \[ 4ac = 4 \times 5 \times 8 = 160 \] \[ b^2 - 4ac = 36 - 160 = -124 \]
Since the discriminant is negative, we will have complex solutions. Now we substitute \(b\), the square root of the discriminant, and \(a\) into the quadratic formula:
\[ x = \frac{-(-6) \pm \sqrt{-124}}{2 \times 5} \] \[ x = \frac{6 \pm \sqrt{-124}}{10} \]
Next, we simplify \(\sqrt{-124}\):
\[ \sqrt{-124} = \sqrt{124}i = \sqrt{4 \times 31}i = 2\sqrt{31}i \]
Now, substituting this back into the quadratic formula gives:
\[ x = \frac{6 \pm 2\sqrt{31}i}{10} \]
We simplify this fraction:
\[ x = \frac{6}{10} \pm \frac{2\sqrt{31}i}{10} \] \[ x = \frac{3}{5} \pm \frac{\sqrt{31}}{5}i \]
The solutions can be presented as:
\[ x = \frac{3}{5} \pm \frac{\sqrt{31}}{5}i \]
Thus, the final answer is:
\[ \frac{3}{5} \pm \frac{\sqrt{31}}{5}i \]