To solve for the prices of the regular and 3-D tickets, we can define:
- \( x \): the price of a regular ticket
- \( y \): the price of a 3-D ticket
From the problem, we know that:
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The price of a 3-D ticket costs $2.00 more than a regular ticket. This can be represented by the equation: \[ y = x + 2 \]
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Oliver bought five regular tickets and four 3-D tickets for a total of $89. This can be represented by the equation: \[ 5x + 4y = 89 \]
Putting these two equations together, we have the following system:
\[ \begin{cases} y = x + 2 \ 5x + 4y = 89 \end{cases} \]
Thus, the correct choice for the system of equations is:
y = x + 2 and 5x + 4y = 89.
Answer: y = x + 2; 5x + 4y = 89.