what's the base of 1 to the power of 9 times 1 to the power of 8

Answer 1

To evaluate the expression \(1^9 \times 1^8\):

Using the properties of exponents, we know that \(a^m \times a^n = a^{m+n}\).

In this case:

\[ 1^9 \times 1^8 = 1^{9+8} = 1^{17} \]

Now, since any power of 1 is simply 1:

\[ 1^{17} = 1 \]

Therefore, \(1^9 \times 1^8 = 1\).