Solve for x in the following equation: 272x−5+1=2

Question

.(1 point)
Responses

16
16

0
0

8
8

11
11
Remaining Attempts : 3

Answer 1

To solve the equation \( 272^{x-5} + 1 = 2 \), we can follow these steps:

1. Start by isolating the exponential term. Subtract 1 from both sides: \[ 272^{x-5} = 1 \]

2. Since \( 272^0 = 1 \), we can set the exponent equal to 0: \[ x - 5 = 0 \]

3. Solve for \( x \): \[ x = 5 \]

Now we check the choices provided:

• 16
• 0
• 8
• 11

None of these are equal to 5. Please check if there are any alternative expressions or parameters in the equation or more possible choices that include the correct answer.