Question
Use the image to answer the question.
A line segment on a coordinate plane. Both the x-and y-axes range from negative 3 to 4 in unit increments. The line segment descends from upper A on the top left to upper B on the bottom right.
Find midpoint M
of the line segment with endpoints A(−1.4,2.5)
and B(2.6,−1.5)
. Enter both responses as a decimal value to the tenth place.
(1 point)
The midpoint of segment AB¯¯¯¯¯¯¯¯
is (
,
).
Remaining Attempts : 3
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A line segment on a coordinate plane. Both the x-and y-axes range from negative 3 to 4 in unit increments. The line segment descends from upper A on the top left to upper B on the bottom right.
Find midpoint M
of the line segment with endpoints A(−1.4,2.5)
and B(2.6,−1.5)
. Enter both responses as a decimal value to the tenth place.
(1 point)
The midpoint of segment AB¯¯¯¯¯¯¯¯
is (
,
).
Remaining Attempts : 3
Skip to navigation
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the midpoint \( M \) of the line segment with endpoints \( A(-1.4, 2.5) \) and \( B(2.6, -1.5) \), you can use the midpoint formula:
\[
M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( B \).
Substituting in the values:
- \( x_1 = -1.4 \)
- \( y_1 = 2.5 \)
- \( x_2 = 2.6 \)
- \( y_2 = -1.5 \)
Calculating the x-coordinate of the midpoint:
\[
M_x = \frac{-1.4 + 2.6}{2} = \frac{1.2}{2} = 0.6
\]
Calculating the y-coordinate of the midpoint:
\[
M_y = \frac{2.5 + (-1.5)}{2} = \frac{1.0}{2} = 0.5
\]
Thus, the midpoint \( M \) of segment \( AB \) is:
\[
M(0.6, 0.5)
\]
The final answer, rounded to the tenth place, is:
The midpoint of segment \( AB \) is \( (0.6, 0.5) \).
\[
M(x, y) = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
\]
where \( (x_1, y_1) \) are the coordinates of point \( A \) and \( (x_2, y_2) \) are the coordinates of point \( B \).
Substituting in the values:
- \( x_1 = -1.4 \)
- \( y_1 = 2.5 \)
- \( x_2 = 2.6 \)
- \( y_2 = -1.5 \)
Calculating the x-coordinate of the midpoint:
\[
M_x = \frac{-1.4 + 2.6}{2} = \frac{1.2}{2} = 0.6
\]
Calculating the y-coordinate of the midpoint:
\[
M_y = \frac{2.5 + (-1.5)}{2} = \frac{1.0}{2} = 0.5
\]
Thus, the midpoint \( M \) of segment \( AB \) is:
\[
M(0.6, 0.5)
\]
The final answer, rounded to the tenth place, is:
The midpoint of segment \( AB \) is \( (0.6, 0.5) \).
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