Given circle P centered at the origin, with a radius of 4 units.

circle p is not a function
domain: -4 less than or equal to times less than or equal to 4
0->3
1->7
2->11
3->15
x^2+ y^2=16
choose all that apply

1 answer

To analyze the details you provided, let's break it down step by step:

  1. Circle P: You've mentioned that circle P is centered at the origin (0, 0) with a radius of 4 units. The equation of this circle is \(x^2 + y^2 = 16\) (since \(4^2 = 16\)). This circle includes all points that are 4 units away from the origin.

  2. Domain: You've stated the domain as \(-4 \leq x \leq 4\). This is correct for the horizontal extent of the circle since the circle stretches from -4 to 4 on the x-axis.

  3. Not a Function: A circle is not a function because it does not pass the vertical line test; for many x-values, there are multiple corresponding y-values.

  4. Mapping Inputs to Outputs: You've provided pairs:

    • \(0 \to 3\)
    • \(1 \to 7\)
    • \(2 \to 11\)
    • \(3 \to 15\)

    These mappings suggest you are defining a relationship or function, but they do not seem to relate directly to circle P or its points because they're not constrained by the equation \(x^2 + y^2 = 16\).

  5. Understanding What to Choose: You mention "choose all that apply," but there are no specific options provided. However, from the context, we can state that:

    • The equation \(x^2 + y^2 = 16\) represents the circle.
    • The statement that circle P is not a function is true.
    • The domain provided matches the circle's x-values.
    • The pairs you provided as mappings do not seem to fit within the context of circle P.

If you have a specific list of options or choices, feel free to provide them, and I can help you determine which of those apply!