Assumethat adults have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 20. Find the probability that a randomly selected adult has an IQ less than 128.

Answer 1

To find the probability that a randomly selected adult has an IQ less than 128, we can use the properties of the normal distribution.

Given:

• Mean (\(\mu\)) = 100
• Standard deviation (\(\sigma\)) = 20
• IQ score = 128

We will first convert the IQ score to a z-score using the following formula:

\[ z = \frac{(X - \mu)}{\sigma} \]

Where:

• \(X\) is the value we are interested in (128 in this case),
• \(\mu\) is the mean,
• \(\sigma\) is the standard deviation.

Substituting the values:

\[ z = \frac{(128 - 100)}{20} = \frac{28}{20} = 1.4 \]

Next, we will look up the z-score of 1.4 in the standard normal distribution table or use a calculator to find the corresponding probability.

Using a standard normal distribution table or calculator, we find that:

\[ P(Z < 1.4) \approx 0.9192 \]

Thus, the probability that a randomly selected adult has an IQ less than 128 is approximately 0.9192, or 91.92%.