Question
Subtract minus, 2, x, squared, minus, 2, x, minus, 7−2x
2
−2x−7 from 2, x, squared, plus, 72x
2
+7.
2
−2x−7 from 2, x, squared, plus, 72x
2
+7.
Answers
GPT-4o mini
To subtract the expression \(-2x^2 - 2x - 7\) from \(2x^2 + 7\), we can set up the calculation as follows:
\[
(2x^2 + 7) - (-2x^2 - 2x - 7)
\]
When we subtract the second expression, we distribute the negative sign:
\[
2x^2 + 7 + 2x^2 + 2x + 7
\]
Now combine like terms:
- The \(x^2\) terms: \(2x^2 + 2x^2 = 4x^2\)
- The \(x\) terms: \(2x\)
- The constant terms: \(7 + 7 = 14\)
Putting it all together, we have:
\[
4x^2 + 2x + 14
\]
So the final result is:
\[
\boxed{4x^2 + 2x + 14}
\]
\[
(2x^2 + 7) - (-2x^2 - 2x - 7)
\]
When we subtract the second expression, we distribute the negative sign:
\[
2x^2 + 7 + 2x^2 + 2x + 7
\]
Now combine like terms:
- The \(x^2\) terms: \(2x^2 + 2x^2 = 4x^2\)
- The \(x\) terms: \(2x\)
- The constant terms: \(7 + 7 = 14\)
Putting it all together, we have:
\[
4x^2 + 2x + 14
\]
So the final result is:
\[
\boxed{4x^2 + 2x + 14}
\]