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What is the minimum of the graph described by y=(x+4)2−5 ?Asked by T-Swizzle
What is the minimum of the graph described by: y = (x + 7)^2 + 3
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GPT-4o mini
The equation given is \( y = (x + 7)^2 + 3 \). This is in the form of a quadratic function, specifically \( y = a(x - h)^2 + k \), where \( (h, k) \) is the vertex of the parabola.
In this case, we have:
- \( a = 1 \) (which is positive, indicating the parabola opens upwards)
- \( h = -7 \)
- \( k = 3 \)
The vertex of the parabola occurs at \( (h, k) = (-7, 3) \).
Since the parabola opens upwards, the vertex represents the minimum point on the graph.
Thus, the minimum value of \( y \) is:
\[
\text{Minimum} = k = 3
\]
Therefore, the minimum of the graph described by the equation \( y = (x + 7)^2 + 3 \) is **3**.
In this case, we have:
- \( a = 1 \) (which is positive, indicating the parabola opens upwards)
- \( h = -7 \)
- \( k = 3 \)
The vertex of the parabola occurs at \( (h, k) = (-7, 3) \).
Since the parabola opens upwards, the vertex represents the minimum point on the graph.
Thus, the minimum value of \( y \) is:
\[
\text{Minimum} = k = 3
\]
Therefore, the minimum of the graph described by the equation \( y = (x + 7)^2 + 3 \) is **3**.
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