To solve the problem, we start with the given polynomial function:
\[ f(x) = -2x^4 + 6x^3 + 10x^2 - 6x - 8 \]
Part 1: Solving \( f(x) = 0 \)
To determine where \( f(x) = 0 \), we can examine the roots that correspond to where the graph intersects the x-axis:
Based on your description of the graph:
- It passes through the x-axis at approximately \( x = -1 \)
- It also has a root around \( x = 1 \)
- Finally, there is another root around \( x = 4 \)
Thus, the solutions for \( f(x) = 0 \) appear to be \( x = -1, x = 1, \) and \( x = 4 \).
This aligns with option D. Therefore, the solution is:
Answer for Part 1: D. \( x = -1, x = 1, \) and \( x = 4 \)
Part 2: Factorization of \( f(x) \)
To find the factorization of \( f(x) \), we can express \( f(x) \) as a product of its factors based on the roots we discovered:
Since the roots are \( x = -1, x = 1, \) and \( x = 4 \), the corresponding factors will be:
- For \( x = -1 \): \( (x + 1) \)
- For \( x = 1 \): \( (x - 1) \)
- For \( x = 4 \): \( (x - 4) \)
Considering the multiplicity of the roots and the leading coefficient:
The polynomial can be expressed in factored form. Since the leading coefficient of \( f(x) \) is \( -2 \), the complete factorization incorporating the leading coefficient would be:
\[ f(x) = -2(x + 1)(x - 1)(x - 4) \]
Thus, the factorization of \( f(x) \) is:
Answer for Part 2: \( f(x) = -2(x + 1)(x - 1)(x - 4) \)
In conclusion:
- Part 1: D. \( x = -1, x = 1, x = 4 \)
- Part 2: \( f(x) = -2(x + 1)(x - 1)(x - 4) \)