Question
The number in the box is _____ and this is a form of _____ decay.
225/88 Ra - 0/-1 e + ___/89 Ac
225/88 Ra - 0/-1 e + ___/89 Ac
Answers
GPT-4o mini
To solve the decay equation given:
\[
^{225}_{88} \text{Ra} \rightarrow ^{0}_{-1} \text{e} + \, ^{___}_{89} \text{Ac}
\]
1. The initial atom is Radium-225 (\(^{225}_{88} \text{Ra}\)).
2. A beta decay (\(0/-1 \text{e}\)) is taking place, which means that one of the neutrons in the Radium nucleus is converted into a proton, increasing the atomic number by 1.
3. The new element formed will have an atomic number of 89, which corresponds to Actinium (\(Ac\)).
Now we can calculate the mass number of the new element:
- The mass number of the original Radium is 225. Since beta decay does not change the mass number (1 neutron is converted to 1 proton), the mass number of Actinium will also be 225.
Thus, we have:
\[
^{225}_{88} \text{Ra} \rightarrow ^{0}_{-1} \text{e} + ^{225}_{89} \text{Ac}
\]
Therefore, the number in the box is **225** and this is a form of **beta** decay.
\[
^{225}_{88} \text{Ra} \rightarrow ^{0}_{-1} \text{e} + \, ^{___}_{89} \text{Ac}
\]
1. The initial atom is Radium-225 (\(^{225}_{88} \text{Ra}\)).
2. A beta decay (\(0/-1 \text{e}\)) is taking place, which means that one of the neutrons in the Radium nucleus is converted into a proton, increasing the atomic number by 1.
3. The new element formed will have an atomic number of 89, which corresponds to Actinium (\(Ac\)).
Now we can calculate the mass number of the new element:
- The mass number of the original Radium is 225. Since beta decay does not change the mass number (1 neutron is converted to 1 proton), the mass number of Actinium will also be 225.
Thus, we have:
\[
^{225}_{88} \text{Ra} \rightarrow ^{0}_{-1} \text{e} + ^{225}_{89} \text{Ac}
\]
Therefore, the number in the box is **225** and this is a form of **beta** decay.