One molecule of bromine (Br) and two molecules of potassium chloride (KCl) combine in a reaction. How many atoms are in the products?

To determine how many atoms are in the products of the reaction between one molecule of bromine (Br) and two molecules of potassium chloride (KCl), we first need to identify what the products are and then count the atoms.

When bromine (Br2) reacts with potassium chloride (KCl), the reaction can form potassium bromide (KBr) and potassium chloride. The balanced chemical equation for this reaction can be written as:

\[
Br_2 + 2 KCl \rightarrow 2 KBr + Cl_2
\]

Now, let's break it down:

1. **Reactants**:
- 1 molecule of Br2 contains 2 bromine atoms (Br).
- 2 molecules of KCl contain 2 potassium atoms (K) and 2 chlorine atoms (Cl).

2. **Products**:
- From the balanced equation, 2 molecules of KBr are produced, which contain 2 potassium atoms and 2 bromine atoms.
- 1 molecule of Cl2 is produced, containing 2 chlorine atoms.

Now we count the total number of atoms in the products:

- KBr: 2 K (potassium) + 2 Br (bromine) = 4 atoms
- Cl2: 2 Cl (chlorine) = 2 atoms

Therefore, the total number of atoms in the products is:

\[
4 \text{ (from KBr)} + 2 \text{ (from Cl2)} = 6 \text{ atoms}
\]

So, there are **6 atoms** in the products of the reaction.